<\/span>Ti\u1ebfn h\u00e0nh b\u1eaft l\u00f4 khung 2 ng\u00e0y nu\u00f4i theo th\u1ee9<\/h3>\n
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C\u00e1ch th\u1ee9c nu\u00f4i l\u00f4 khung 2 ng\u00e0y v\u1edbi th\u1ee9 c\u0169ng l\u00e0 g\u1ee3i \u00fd r\u1ea5t \u0111\u00e1ng \u0111\u1ec3 cho ng\u01b0\u1eddi ch\u01a1i tham kh\u1ea3o v\u00e0 l\u1ef1a ch\u1ecdn. Theo \u0111\u00f3, ph\u01b0\u01a1ng th\u1ee9c ch\u01a1i n\u00e0y s\u1ebd \u0111\u01b0\u1ee3c \u00e1p dung v\u1edbi c\u00e1 th\u1ee9 nh\u01b0 sau:<\/p>\n
\u2013 Th\u1ee9 hai: ng\u01b0\u1eddi ch\u01a1i s\u1ebd soi t\u1eeb b\u1ea3ng k\u1ebft qu\u1ea3 l\u00f4 v\u1ec1 ng\u00e0y ch\u1ee7 nh\u1eadt v\u00e0 sau \u0111\u00f3 gh\u00e9p s\u1ed1 \u0111\u1ea7u ti\u00ean c\u1ee7a b\u1ed9 l\u00f4 th\u1ee9 6 trong gi\u1ea3i 5 v\u1edbi b\u1ed9 l\u00f4 th\u1ee9 1 trong gi\u1ea3i 6. Ti\u1ebfn h\u00e0nh nu\u00f4i l\u00f4 khung 2 ng\u00e0y \u0111\u1ec3 c\u00f3 c\u01a1 h\u1ed9i tr\u00fang \u0111\u1eadm.<\/p>\n
\u2013 Th\u1ee9 ba: Xem k\u1ebft qu\u1ea3 l\u00f4 v\u1ec1 ng\u00e0y th\u1ee9 2 r\u1ed3i v\u00e0 ch\u1ecdn con l\u00f4 v\u1edbi t\u1ed5ng c\u1ee7a 2 s\u1ed1 \u1edf b\u1ed9 l\u00f4 th\u1ee9 3 trong gi\u1ea3i 7. Ch\u1eb3ng h\u1ea1n, \u1edf th\u1ee9 2, t\u1ed5ng c\u1ee7a b\u1ed9 l\u00f4 th\u1ee9 3 trong gi\u1ea3i 7 l\u00e0 31. Nh\u01b0 v\u1eady ng\u01b0\u1eddi ch\u01a1i s\u1ebd c\u00f4ng 3+1= 4 v\u00e0 \u0111\u00e1nh con l\u00f4 04 trong 2 ng\u00e0y.<\/p>\n
\u2013 Th\u1ee9 t\u01b0: ti\u1ebfn h\u00e0nh ch\u1ed1t l\u00f4 b\u1eb1ng vi\u1ec7c c\u1ed9ng t\u1ea5t c\u1ea3 c\u00e1c c\u1eb7p s\u1ed1 trong gi\u1ea3i 7 c\u1ee7a th\u1ee9 ba l\u1ea1i v\u00e0 \u0111\u00e1nh con s\u1ed1 l\u00f4 t\u1ed5ng n\u00e0y. Ch\u1eb3ng h\u1ea1n, l\u00f4 gi\u1ea3i 7 c\u1ee7a th\u1ee9 3 l\u00e0: 03 \u2013 10 \u2013 34 \u2013 50. Ta s\u1ebd c\u1ed9ng l\u1ea1i: 32 + 03 + 10 + 43 + 50 = 138. Nh\u01b0 v\u1eady, ta s\u1ebd ch\u1ecdn 38 \u0111\u1ec3 \u0111\u00e1nh.<\/p>\n
\u2013 Th\u1ee9 n\u0103m s\u1ebd l\u00e0 c\u00e1ch \u0111\u00e1nh v\u1edbi vi\u1ec7c gh\u00e9p s\u1ed1 th\u1ee9 2 v\u00e0 s\u1ed1 th\u1ee9 3 trong b\u1ed9 l\u00f4 th\u1ee9 2 gi\u1ea3i 5 ng\u00e0y c\u1ee7a th\u1ee9 4 l\u1ea1i.<\/p>\n
Ti\u1ebfn h\u00e0nh b\u1eaft l\u00f4 khung 2 ng\u00e0y nu\u00f4i theo th\u1ee9<\/h4>\n
\u2013 Th\u1ee9 s\u00e1u \u0111\u00e1nh theo c\u00e1ch gh\u00e9p 2 s\u1ed1 \u0111\u1ea7u thu\u1ed9c gi\u1ea3i 5 v\u00e0 gi\u1ea3i 5.5 trong th\u1ee9 n\u0103m l\u1ea1i v\u1edbi nhau.<\/p>\n
\u2013 Th\u1ee9 b\u1ea3y \u0111\u00e1nh s\u1ed1 b\u1eb1ng vi\u1ec7c c\u1ed9ng t\u1ea5t c\u1ea3 c\u00e1c s\u1ed1 trong gi\u1ea3i 5.5 c\u1ee7a s\u1ed1 l\u00f4 v\u1ec1 trong th\u1ee9 s\u00e1u l\u1ea1i v\u1edbi nhau.<\/p>\n
\u2013 Ch\u1ee7 nh\u1eadt \u0111\u01b0\u1ee3c t\u00ednh s\u1ed1 l\u00f4 theo c\u00e1c gh\u00e9p s\u1ed1 th\u1ee9 nh\u1ea5t v\u00e0 s\u1ed1 th\u1ee9 3 trong b\u1ed9 l\u00f4 th\u1ee9 6 c\u1ee7a gi\u1ea3i 3 ng\u00e0y th\u1ee9 b\u1ea3y.<\/p>\n
Nh\u01b0 v\u1eady, c\u00e1ch ch\u01a1i l\u00f4 khung 2 ng\u00e0y \u0111\u00e3 \u0111\u01b0\u1ee3c g\u1ee3i \u00fd tr\u00ean c\u00f3 gi\u00fap b\u1ea1n hi\u1ec3u h\u01a1n v\u1ec1 c\u00e1ch ch\u01a1i n\u00e0y. H\u00e3y th\u1eed \u00e1p d\u1ee5ng nu\u00f4i l\u00f4 khung 2 ng\u00e0y v\u1edbi c\u00e1c k\u00e8o l\u00f4 soi c\u1ea7u x\u1ed5 s\u1ed1 t\u1ea1i v\u00e0 cho ch\u00fang t\u00f4i bi\u1ebft hi\u1ec7u qu\u1ea3 c\u1ee7a n\u00f3 nh\u00e9!<\/p>\n